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rotate_img.py
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'''
You are given an n x n 2D matrix representing an image, rotate the image by 90 degrees (clockwise).
You have to rotate the image in-place, which means you have to modify the input 2D matrix directly.
DO NOT allocate another 2D matrix and do the rotation.
Example 1:
Input: matrix = [[1,2,3],[4,5,6],[7,8,9]]
Output: [[7,4,1],[8,5,2],[9,6,3]]
Example 2:
Input: matrix = [[5,1,9,11],[2,4,8,10],[13,3,6,7],[15,14,12,16]]
Output: [[15,13,2,5],[14,3,4,1],[12,6,8,9],[16,7,10,11]]
Constraints:
n == matrix.length == matrix[i].length
1 <= n <= 20
-1000 <= matrix[i][j] <= 1000
'''
# With use of a help matrix
def rotate(matrix):
"""
:type matrix: List[List[int]]
:rtype: None Do not return anything, modify matrix in-place instead.
"""
n = len(matrix)
row = []
rotated_matrix = []
for j in range(n):
for i in range(n):
row.append(matrix[i][j])
row.reverse()
rotated_matrix.append(row[:])
row = []
matrix = rotated_matrix
return matrix
def rotateInPlace(matrix):
"""
:type matrix: List[List[int]]
:rtype: None Do not return anything, modify matrix in-place instead.
"""
n = len(matrix)
# Transpose the matrix in place
for i in range(n):
for j in range(i+1, n):
matrix[i][j], matrix[j][i] = matrix[j][i], matrix[i][j]
# Reverse each row in place
for i in range(n):
matrix[i].reverse()
return matrix
# Some Test cases
if __name__ == "__main__":
matrix1 = [[1,2,3],
[4,5,6],
[7,8,9]]
output1 = [[7,4,1],
[8,5,2],
[9,6,3]]
matrix2 = [[5,1,9,11],
[2,4,8,10],
[13,3,6,7],
[15,14,12,16]]
output2 = [[15,13,2,5],
[14,3,4,1],
[12,6,8,9],
[16,7,10,11]]
matrix3 = []
output3 = []
# Examples
input = [
(matrix1, output1),
(matrix2, output2),
(matrix3, output3)
]
for idx, (matrix, expected) in enumerate(input):
print("\nExample", idx, ":")
print("Input:", matrix)
print("Output:", rotateInPlace(matrix))
print("Expected:", expected)