From 0e55b3454a4c2528d23bb61c74814958ca890767 Mon Sep 17 00:00:00 2001
From: nessan Examples
last
” element.
+Construct a vector of size 12 and then attempt to set the “last” element.
That is not true for vectors over \(\FF\).
For example, if \(\mathbf{v} = \{1, 1\}\) is thought of as a vector over \(\FF\) then \[
\mathbf{v} \cdot \mathbf{v} = \{1, 1\} \cdot \{1, 1\} = 1 + 1 = 2 \rightarrow 0 \text{ mod 2}.
@@ -623,7 +627,7 @@ Suppose that \(A\) is an \(n \times n\) matrix over \(\FF\) and \(b\) is a compatibly sized bit-vector where we are interested in finding an \(x\) satisfying \(A \cdot x = b\). Then the pseudocode for Gaussian elimination looks like: There isn’t a lot of material on the web devoted to linear algebra over GF(2). There isn’t a lot of material on the web devoted to computational work in GF(2).Some things are si
Gaussian Elimination in \(\FF\)
Technical Notes
Introduction
-
+
We add some here: