-
Notifications
You must be signed in to change notification settings - Fork 0
/
Copy pathProblem_0061_rotateRight.cc
75 lines (70 loc) · 1.29 KB
/
Problem_0061_rotateRight.cc
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
#include <vector>
using namespace std;
struct ListNode
{
int val;
ListNode* next;
ListNode() : val(0), next(nullptr) {}
ListNode(int x) : val(x), next(nullptr) {}
ListNode(int x, ListNode* next) : val(x), next(next) {}
};
class Solution
{
public:
// 反转链表
ListNode* reverse(ListNode* head)
{
ListNode* pre = nullptr;
ListNode* cur = head;
ListNode* next = nullptr;
while (cur != nullptr)
{
next = cur->next;
cur->next = pre;
pre = cur;
cur = next;
}
return pre;
}
ListNode* rotateRight(ListNode* head, int k)
{
if (k == 0 || head == nullptr)
{
return head;
}
int n = 0;
ListNode* cur = head;
// 求链表一共多少个节点
while (cur != nullptr)
{
n++;
cur = cur->next;
}
k %= n;
k = n - k;
cur = head;
ListNode* pre = nullptr;
while (k-- != 0)
{
pre = cur;
cur = cur->next;
}
// 断开链表
pre->next = nullptr;
// 反转前 n - k 个
ListNode* l = reverse(head);
// 反转后 k 个
ListNode* r = reverse(cur);
cur = l;
while (cur != nullptr)
{
pre = cur;
cur = cur->next;
}
// 拼接链表
pre->next = r;
// 反转整个链表
r = reverse(l);
return r;
}
};