Formatting (#141)

packages/smath/examples/Tangent Line.md

@@ -2,14 +2,14 @@
 
 The tangent line to a curve is a line that passes through a single local point on the curve, that also matches the same slope. That means, the derivative of the curve must match the slope of the tangent line.
 
-Let's assume our curve is defined by the formula below and we want to find the tangent line at $x_{0}=1$.
+Let's assume our curve is defined by the formula below and we want to find the tangent line at \(x_{0}=1\).
 
 $$f(x) = \frac{1}{8}x^{2} - x - 4$$
 
-We could plug in $f(x_{0})$ to obtain $y_{0}$, then compute the derivative $f'(x_{0})$ to obtain the slope, and then plug in our values into point-slope form.
+We could plug in \(f(x_{0})\) to obtain \(y_{0}\), then compute the derivative \(f'(x_{0})\) to obtain the slope, and then plug in our values into point-slope form.
 
 $$y-y_{0}=m(x-x_{0})$$
 
-Finally, we can rewrite this formula in y-intercept form $y=mx+b$ where $b=y_{0}-mx_{0}$.
+Finally, we can rewrite this formula in y-intercept form \(y=mx+b\) where \(b=y_{0}-mx_{0}\).
 
 $$y=mx+(y_{0}-mx_{0})$$